a]
The distance of the retina from the cornea is approximately 1.7cm.
We know that the magnification for a lens is given by m = -v / u = h2 / h1.
Thus, m = +1.7 cm / (20 x 2.54) cm = 0.0335
=> himage / hobject = 0.0335
Now from the given data, angle subtended at retina, we can calculate himage as:
himage = (subtended angle in radians) x (image distance)
himage = 2.473 x 10-3 cm
hobject = himage / m = 0.074 cm = 0.74 mm
Thus the smallest possible height of the icons/characters for 20/20 vision is 0.74 mm.
b]
Since the object has moved farther away, the pupil increases its diameter in order to allow more light in. Also, the ciliary muscles contract, flattening the lens in order to focus the object which is now at a greater distance.
c]
Monocular depth cues that allow depth perception can be stated as follows:
A worker uses a computer monitor at a viewing distance of 20 inches (a) What would...
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