Question
Please help break down
1. Molaroty unknown, mmol/ml
2. Average molarity of unknown
3. Relative average deviation
20.000ル 20.00ル 26001c volume of NaOH used, mL Molarity of NaOH, mmol/ml Average molarity of unknown Relative average deviatio
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Vacid*Macid = VNaOH *MNaOH (1)

Trial 1

VNaOH = 20.00 ml. MNaOH = 0.990 M

Vacid = 22.60 ml, Macid = X M

using Eq.1

20.00*0.990 = 22.60*X

or, X = (20.0*0.990) /22.60 = 0.8761 M = 876.1 mmol/ L

Trial 2

VNaOH = 20.00 ml , MNaOH = 0.990

Vacid  = 22.30 ml , Macid = X M

using Eq.1

20.00*0.990 = 22.30*X

or, X = (20.00*0.990)/22.30 = 0.8878 M = 887.8 mmol/ L

Trial 3

VNaOH = 20.00 ml, MNaOH = 0.990 M

Vacid = 22.60 ml, Macid = X M

Using Eq.1

20.00*0.990 = 22.60*X

or, X = (20.00*0.990)/22.60 = 0.8761 M = 876.1 mmol/ L

hence, Average molarity ( \mu)

= ( 0.8761 + 0.8878 + 0.8761)/3 = 0.88 M = 880 mmol/ L

Now, average deviation = \sum ( |\mu - x)|/n

\mu is average, x is data value, n is number of trials

= (|0.88 - 0.8761|)+(|0.88 - 0.8878|) +(|0.88 - 0.8761|) /3

= (0.0039+0.0078+0.0039)/3

= 0.0052

Relative average deviation = average deviation *100 = 0.0052*100 = 0.52

Add a comment
Know the answer?
Add Answer to:
Please help break down 1. Molaroty unknown, mmol/ml 2. Average molarity of unknown 3. Relative average...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 1. Volume of Vinegar used in each trial = 5.00 mL 2. Molarity of NaOH used...

    1. Volume of Vinegar used in each trial = 5.00 mL 2. Molarity of NaOH used in each trial = 0.20M 3. Volume of NaOH used in trail#1 (Final – Initial buret reading) = __17.80______ mL 4. Volume of NaOH used in trail#2 (Final – Initial buret reading) = ___18.20_____ mL 5. Average Volume of NaOH used = (#3 + #4) / 2 = ___18______ mL 6. Calculate Molarity of Acetic acid in vinegar = _________ M ?????? (molarity of...

  • Please help me find the molarity of NaOH, the average molarity and Standard deviation please. I...

    Please help me find the molarity of NaOH, the average molarity and Standard deviation please. I will give a thumbs up. REPORT SHEET : EXPERIMENT Determination of the 8 Dissociation Constant of a Weak Acid B. Standardization of Sodium Hydroxide (NaOH) Solution Trial 1 Trial 2 Trial 3 Mass of bottle+KHP Mass of bottle Mass of KHP used 0.218 Final buret reading 13.9133 ha Initial buret reading mL of NaOH used Molarity of NaOH Average molarity (show calculations and standard...

  • moles of oxalix acid moles/molarity of NaOH average molarity volume/molarity of hcl used average molarity NAME...

    moles of oxalix acid moles/molarity of NaOH average molarity volume/molarity of hcl used average molarity NAME SECTION DATA SHEET LOCKER A CTOR Write a balanced equation for the reaction between H.CO. and NaOH: 90.33/mol 0.878 0836 TRIAL NUMBER a. Mass of oxalic acid used (g) b. Final Buret reading (ml.] c. Initial Buret reading (ml] d. Volume of NaOH used (b-c) Moles of oxalic acid used f. Moles of NaOH used (2 xe) g. Molarity of NaOH (f/d/1000) Average Molarity...

  • Section DATA SHEET: EXPERIMENT 16 Date A. Determination of NaOH Concentration 1. Molarity of HCl solution...

    Section DATA SHEET: EXPERIMENT 16 Date A. Determination of NaOH Concentration 1. Molarity of HCl solution M Trial #1 Volume of acid 0.0831 Trial #2 Trial #3(...) 25.00 ml 25.00_ml 25.00 ml 160.40 ml 5.55_ml 18.75 ml 1.30_mi 0.25_ml. 3.80 ml 3. Final buret reading Initial buret reading 5. Volume of NaOH - 6. Molarity of NaOH (Show set-up) 7. Average molarity of NaOH Analysis of Vinegar (Acetic Acid) Advertised % Acetic Acid Trial #1 Trial #2 Trial #3(...) Volume...

  • Experiment 10 An Acid-Base Neutralization Reaction A. Determination of Unknown Acid Concentration Trial Trial 2 Tri...

    Experiment 10 An Acid-Base Neutralization Reaction A. Determination of Unknown Acid Concentration Trial Trial 2 Trial 3 Trial 4 Volume of acid 10m 10m 10m 10mL Final buret reading- NaOH (mL) To.8ML 23.8ml 26.2m4 29.4m Initial buret reading- NaOH (mL) Volume of NaOH required to reach the end point. V 10.8m. 13ML 2.4mL 3.2mL Molarity of the acid, M. 10. OmL/108m./23.8mL 26.2mL) Unknown acid number: 16 Molarity of NaOH: Average Molarity of acid 0-1076m Show all calculations for trials 1...

  • can you help with the balance equation and also the calculations at the bottom of the...

    can you help with the balance equation and also the calculations at the bottom of the sheet thank you Experiment 17 Acid Base Reactions and Titration Report Sheet Name Section Number Provide the balanced equation for standardizing NaOH below. Table L. Standardization of NaOH Trial Trial 2 Trial 3 Initial mass of flask (g) 85.85 92.9285.80 Mass of flask with KHP (g) Initial buret reading of NaOH (mL) 11.87 19.21 4.21 Initial-buret-reading of NaOH (mL) Final buret reading of NaOH...

  • Please help calculate, Concentration of NaOH is 0.1M. Trial 2 Trial 3 Trial 1 C. #502...

    Please help calculate, Concentration of NaOH is 0.1M. Trial 2 Trial 3 Trial 1 C. #502 0.8236g 0.8389g Mass of impure KHP unknown taken (g 0.8167g 0.00mL. 0.00mL 0.00ml. Initial burette reading (mL) 27.52 mL Final burette reading (mL) 27.52 mL 27.87mL 26,72mL Volume of NaOH used (mLO by mass of impure KHP unknown relative average deviation Trial 1 Trial 2 Trial 3 D. #11 0.3602g 0.3636g Mass of unknown acid (g) 0.00ml 0.00mL 10.00mL Initial burette reading (mL) 5.88mL...

  • exp UDAS TIL ALIUL Part B. Determine 1 • Determine the Molarity of an Unknown hydrochloric...

    exp UDAS TIL ALIUL Part B. Determine 1 • Determine the Molarity of an Unknown hydrochloric acid solution Volarity of standardized NaOH solution Trial 1 Trial 2 Buret A Buret B Buret A Buret A Buret B Trial 3 Buret B Buret reading at start 16 .15 10 .10 25.75 14.20 24.99 13.52 25.60 14.05 24.89 13.42 Buret reading at end Volume of solution mL Molarity of HCI solution Average Molarity Average Deviation RAD 10.0482 m 10.04765m Show calculations here:...

  • B. Analysis of an unknown Acid Trial 1 Mass of bottle + unknown 1.9762 g Mass...

    B. Analysis of an unknown Acid Trial 1 Mass of bottle + unknown 1.9762 g Mass of bottle 1.0317 g Mass of unknown used 0.9445 g Final buret reading 21.40 mL Initial buret reading 1.05 ml mL of NaOH used 20.35 ml Mass of KHP used 0.4833 g Percent of KHP Trial 2 1.9557 g 1.0317 g 0.9240 g 39.90 mL 20.05 ml 19.85 ml 0.4714g Trial 3 1.9813 g 1.0317 g 0.94468 41.05 mL 20.65 ml 20.40 mL 0.48458...

  • Questions: A. From the standardization data, calculate the molarity of the sodium hydroxide solution for each...

    Questions: A. From the standardization data, calculate the molarity of the sodium hydroxide solution for each trail. Average the values and enter the average in the Standardization Data Table. B. From the equivalent mass data, calculate the equivalent mass of the unknown acid for each trial. Average the values and enter the average in the Equivalent Mass Data Table. Acid-Base Titrations continued Standardization Data Table Trial 1 Trial 2 Trial 3 Mass KHP Final Volume, mL Initial Volume, ml Volume...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT