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Reinforcement Problem # 4 (25 pts.) A) Given For an AC electric power circuit given: 10KW 25040 Vms 0.81ag B) Determine Step 1: The values for the load average power PL, reactive power QL, and complex power SL Step 2: The value of the line current Step 3: The value of the line average power Pi, reactive power α, and complex power Step 4: The value of the power factor of the entire electrical power circuit (seen by source generator). Step 5: The value of the required line voltage Vg of the power system generator Step 6: The value of the equivalent impedance of the 10 KW load. Evaluation Criteria Rubric for Reinforcement Problem 4 Activities Step 1 Step 3 Step 6 oints 5.0 points 3.0 points 5.0 points 3.0 points 5.0 points 2.0 points 1.0 points 1.0 points 25.0 points Describe the techniques and procedures you used in each step uare all the answers and include their I dimensions, if a TOTAL
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sterd, Determination af FL h 0,25 010 pouser) a SL COTrplex power From Loqd side,Glveのdafa are: lokal, P.f=0,8 lag-asPL lo kw rmsLag Laverage loacl Power, (reachve I R = 10 kW kachve Average load ) ค.= (sl cos p ( d(R-Jm] ass umin g load lagg Complex power magnihde Comp I en Polar Form (lokw +丁チ5)-( Rectangular form ) Cabsorbed) step? The value of-Line ce rre아 1: R 250 Watt rms | Sp-559 VA St-250.+ J560-559L6343stepa ecftve power OOS 4ケー effechv Eff step67、 Vg_? From po er (Balance) (0.25 kW 26°. 15m - rms gtry二260 ,15 Vol+ 丘のpedance o kul load Equivalent Empe SL 12 5 kVA ZL= 5.al 35% bansIncase any assistance , please feel free to ask. I will be happy to help you. Thank$!

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