Question

me are modeled by the differential equation, 1) (0) Recall that spring mass systems are mos ky FD A force of 180 newtons stretches a spring constant of 360N A mass of so kilograms spring and is initially released from resta equilibrium point. The motion is undamped es a spring 0.5 meters, which gives a spring 0 kilograms is attached to the end of the od from rest at a point 0.25 meters above the undamped Set up an initial value problem then find the equation of motion

Answer 1

solution:- Here we we have Given that, consider in Chenna) to use Partial fraction 25 +8 s3ths of i 25+825+8 33+45 515444) = + 2-28 - Apply Inverse 5074 Lapiace Tx on Big <1% (!)+" (en 2-27 24 =&L" []J+i 4*) - 22" (zn) we know that , 17 1 [ Jai il serait ) = sin cat) in the body - cos lat)

< 2 [1] + sin(at)- 2005 (@t) = 2 + sinat +2 Cosat Hence solved, please Rate" It HEI PF US-T.Q