Question
Differntial Equations Forced Spring Motion

1. A 1 kg mass is attached to a spring of spring constant k = 4kg/82, The spring-mass system is attached to a machine that su
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Answer #1

Here total force on 1kg mass is given by

f (t)- kr and acceleration is written as {x}'' then

f(t)-kx = m{x}''
or
m{x}''=f(t)-kx
or
kr 4 r =--+-cos(wt) ?7m ?7m

Now by integrating

sunlu ?7m
here C1=0 as x'(0) =0

hence

sunlu ?7m
Now by farther integration

4cos(ut

here
mu2 as x(0) =0

now equation become

x(t)=-\frac{kx}{2m}\times t^{2}-\frac{4}{m\omega^{2} }\times cos(\omega t)+\frac{4}{m\omega^{2} }

by substituting value of m=1kg k=4  and mmu

- COsl

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