Question

of liquid water and 0.9 m2 of water vapor in equilibrium at 600 kPa. Heat is transferred at constant pressure until the temperature 3-51 A piston-cylinder device contains 0.005 m reaches 200°C What is the initial temperature of the water Determine the total mass of the water Chlouwle the final volume. Show the process on a pu diagram with respect to s tation lines. HO P600 kPa FIGURE P3-51

Answer 1

Let us solve this problem step by step: Step 1: Write all the given data - Viq=0.005 m3 Vapew = 0.9 m3 L P = 6ookpa and p = 600kpa - I = 200°C SC Step 2. - using the saturated water tables, at p = Gooupa, ; T = That = 158.83° c . 0 C Step 3:- From the data we have VE = 0.00110 m3) ky vg = 0.3156 m², kg mia = vir = liq 0.005 0.colloi VE 4.54.1 K

= map - Viap = 2.85176 0.9 0:3156 - step 4: We know that, total mas, -> m=mlig tmvap m= 4.541 + 2.8517 m=7.3927 kg so, m = 7.3927 kg Step 5: using Table - At p = 6ookpad T = 200 35212 mily and we know that y = mo tv - V = 7.939 x 0.352 - 2 = 2.603 m3 Step 6: Draw the process on PD diagram