Question

14. A hummingbird of mass 2.50 g consumes 65.0 ml of O, (at 27°C and 1 atm) per hour of flight. According to the unbalanced chemical equation: C6H12O6 (aq.) + O2(g) – CO2(g) + H2O(g) + AH a. How many mL of oxygen will the hummingbird need to gather to complete a five hour flight? Answer (enclose work) b. If glucose supplies all the needed energy, what is the minimum mass of glucose that the hummingbird must gather from plants for each five hours of flight? Answer (enclose work) c. How much energy will the hummingbird need to obtain from glucose to complete the five hour flight if AH = -2800 kJ/mol? Answer (enclose work)

Answer 1

CHI OG + 6 02 (9) - 6 CO₂ (g) + 6H₂O(g) + oH o for & hour flight de requined - 65 mL for s hour flight Op required = 5x65 = 325 ML 102 = 325ml moles of O2 consumed - Py = nRT 1 x 0.325 0.0821 X 300 - 0.0 132 of I mole moles of glucose uses 6 mole of O2 glucose used = txo -0.0022 gleccose = moles & molar mass of glucose weight of -0.0022 X 180 I weight of glucose = 0.396 gml. I mole for glucose gives 2800 kJ chagya 0.0022 mole of glucose E = 0.0022 x 2800 kJ E = 6.16 KJ