Given,
h = 10 cm ; d = 40cm
R = D/2 and F = R/2
F = D/4 = 40/4 = 10 cm
We know from lens eqn
1/f = 1/i + 1/o
i = o x f/(o - f)
o = 5 cm
1)i = 5 x 10/(5 - 10) = -10 cm
i = 10 cm (from the mirror)
2)M = -i/o = h'/h
h' = 10/5 x 10 = 20 cm
h' = 20 cm
3)The image is Virtual
4)D = 5 + 10 = 15 cm
D = 15 cm
o = 10 cm
1)i = 10 x 10/(10 - 10) = infinity
i = infinity
2)udefined
3)virtual
4)infinite
o = 15 cm
1)i = 15 x 10/(15 - 10) = 30 cm
i = 30 cm
2)h' = -30/15 x 10 = 20 cm
h' = 20 cm
3)Real
4)D = 15 + 30 = 45 cm
o = 25 m = 2500 cm
1)i = 2500 x 10/(2500 - 10) = 10 cm
i = 10 cm
2)h' = 10/2500 x 10 = 0.04 cm
h' = 0.04 cm
3)REAL
4)D = 2500 + 10 = 2510 cm
D = 2510 cm
Example 7 (Concave Mirrors) A 10 (cm) tall object is placed in front of a concave...
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An object is placed 11 cm in front of a concave mirror whose
focal length is 17 cm. The object is 3.2 cm tall. Determine (a) the
location of the image, taking a real image as a positive value and
a virtual image as a negative value. (b) Determine the height of
the image, where an upright image will have a positive height and
an inverted image will have a negative height.
Object
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