Three charges (q1 = 7.4 μC, q2 = -3.5 μC, and q3 = 3.7μC) are located...

Question

Question

Three charges (q₁ = 7.4 μC, q₂ = -3.5 μC, and q₃ = 3.7μC) are located at the vertices of an equilateral triangle with side d = 9.6 cm as shown.

d (42) d d (4)

A charge q₄ = 3.7 μC is now added as shown.

3) What is F_2,x, the x-component of the new net force on q₂?

4) What is F_2,y, the y-component of the new net force on q₂?

5) What is F_1,x, the x-component of the new net force on q₁?

Answer 1

Answer #1

Step 4 Find Far and Fy for 154/= 16:1 0=60° 9x108x 8.5X34X162 0.0962 = 12.64 N Stepa Find Fiz (F12 = 9x109 x 7.4 x 3.871012 0

Please let me know if it was helpful. Thank you!

Answer 2

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