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Constants Part B A 1810 kg elevator with broken cables is falling at 4.70 m/s when...
Constants Part A A 2045 kg elevator with broken cables is falling at 4.60 m/s when it first contacts a cushioning spring at the bottom of the shaft. The spring is supposed to stop the elevator, compressing by 2.80 m as it stops. During the motion a safety clamp applies a constant 1.64x104 N_frictional force to the elevator What is the spring constant of the spring that stops the elevator? Value Units Request Answer Submit Part B What is the...
Page 204 Practice Problem 7.11: If the mass of the elevator (with four what should the spring constant Answer: 2.18x10 N/m. a the spring constant be for a maximum compression of 3.00m? ! is equal to that EXAMPLE 7.11 Elevator safety (or not) to this exoblem we have to account for both gravitational potential energy and elastic potential energy. In a worst-case" design scenario, a 2000 kg elevator with broken cables is falling at 8.00 m/s when it first con...