A buffer solution having a total volume of 0.50 L is prepared which has the following composition: [NH4Cl] = 0.25 M, [NH3] = 0.40 M. [Note: Kb of NH3 = 1.8 × 10−5 ]
(a) Identify the species that acts as the acid and base in this buffer.
(b) What role does the chlorine anion play?
(c) Calculate the pH of this buffer solution using the Henderson-Hasselbalch equation. Is there any underlying assumption being made when you use this equation? Please show your work.
(d) If you added 0.10 moles of HCl to the solution, what would the new pH be? Please show your work. (e) Based on your answer to question (a), determine the buffer range. Please show your work.
(A) In this buffer ammonia acts as the base and ammonium chloride acts as the acid. NH4+ being the conjugate base
(b) chlorine gives the acidity to the buffer. NH4Cl dissociates in water to give ammonium and chlorine ions. the Cl-then associates with water to form HCl which dissociates to give H+ and Cl- ions.
(c)the henderson-hasselbalch equation for this is
pOH= pKb + log {[BH+]/[B]}
= -log(1.8 * 10-5) + log [0.25]/[0.40]
= 4.744 + (-0.204)
= 4.54
pH= 14- pOH = 14-4.54
pH= 9.46
(d) if you add HCl, it will dissociate into H+ and Cl-. the H+ will form H3O+ with water. concentration of HCl is 0.1/0.5(moles/vol)= 0.2M. so [H3O+]=0.2M
the ammonia will now react with these hydronium ions as follows
NH3 + H3O+ -> NH4+ + H2O
I 0.4 0.2 0.25
C 0.4-0.2 -0.2 +0.2
E 0.2 0 0.45
using the hendelsen-hasselbalch equation,
pOH= pKb + log {[BH+]/[B]}
= -log(1.8 * 10-5) + log [0.45]/[0.20]
=4.744 + 0.352
(e) to find the buffer range we need to find the pKa. we are given kb so pKb= -log Kb= 4.744
pKa+ pKb=14
pKa= 14-4.744= 9.25
the buffer range is usually +/- pKa
so, the buffer range anywhere is between 8.25 to 10.25
= 5.096
so pH= 14- pOH= 14-5.096
pH = 8.9
A buffer solution having a total volume of 0.50 L is prepared which has the following...
1. Calculate the pH of a buffer solution which is 0.50M in NH3 and 0.30M in NH4Cl. Given Kb = 1.8 x 10^-5 for NH3. a) Calculate Ka. b) Calculate pKa. c) Calculate pH using the Henderson-Hasselbalch equation.
Use the Henderson-Hasselbalch equation to calculate the pH of each solution: (a) a solution that is 0.20 M in HCHO2 and 0.10 M in NaCHO2. (Ka=1.8×10−4) (b) a solution that is 0.14 M in NH3 and 0.19 M in NH4Cl. (Kb=1.76×10−5)
Use the Henderson-Hasselbalch equation to calculate the pH of each solution: A solution that is 0.14 M in NH3 and 0.20 M in NH4Cl. (Kb= 1.76x10^-5)
Calculate the pH of a buffer prepared by dissolving 0.10 mol of NH4Cl in 1.00 L of 0.15 M NH3. Kb = 1.8 x 10 % for NH3. O a. 11.34 O b. 2.72 O ü O ö Oe. 4.56
if 155 mL of 0.043 M HCl solution is added to 235 mL of a buffer solution which is 0.33 M in NH3 and 0.56 M in NH4Cl, what will be the pH of the new solution? the Kb of NH3 is 1.8*10^-5
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How many grams of dry NH4Cl need to be added to 2.10 L of a 0.500 M solution of ammonia, NH3, to prepare a buffer solution that has a pH of 8.76? Kb for ammonia is 1.8×10−5. Express your answer with the appropriate units.
Consider a buffer solution that is 0.50 M in NH3 and 0.20 M in NH4Cl. For ammonia, pKb=4.75. Calculate the pH of 1.0 L upon addition of 0.090 mol of solid NaOH to the original buffer solution.
Consider a buffer solution that is 0.50 M in NH3 and 0.20 M in NH4Cl. For ammonia, pKb=4.75. Calculate the pH of 1.0 L upon addition of 0.050 mol of solid NaOH to the original buffer solution. Thanks!
How many grams of dry NH4Cl need to be added to 2.50 L of a 0.500 M solution of ammonia, NH3, to prepare a buffer solution that has a pH of 8.74? Kb for ammonia is 1.8*10^-5.