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solve for the unknown molecular structure.
#2 IR Spectrum iquid m 1740 2000 v (em) 800 3000 1600 1200 4000 100 Mass Spectrum 80 No significant UV absorption above 220 n
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Answer #1

The abs. band at near 1740 cm-1 due to ester.

It is aliphatic ester corresponds to C6H12O2.

The mol. ion at m/z 116 , corresponds to C6H12O2.

The ions at m/z 73 due Iso butyloxy group, and m/z 56 and 43 due to removal of -OH and iso propyl group.

In given 1H-nmr, the peak at del 3.85 as a doublet due to -OCH2-CH and peak at del 1.92 as a multiplet due to CH of iso propyl group and peak at del 2.1 as a singlet due to CH3CO.

Hence it is isobutyl acetate.

- In When IR spectrum- Tar is aliphatic ketone Os ester 2) The abs, band at 1740 cm it is characterist yer ester group, In giIn given name at $ 3.85 spectrum doubler -o-cry-ch at sli92 O multiple usefret CH at 8201 Singlet 4²-co- Hence it is iso buty

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