Question

1. The current and voltage for an element are shown below (assume+ for the passive sign convention) a. b. Draw a plot of power for that elemen Find the total energy delivered to the element in 0 to 60 ms. t on the axes provided. [15 pts.] i (mA) 250 10 20 40 50 60 70 (ms) -250 v (V) t (ms) 20 40 50 60 70 p (W) 10 20 30 40 50 60 70 t(ms) 2. The circuit below is a valid interconnection of sources. Find the total power developed in the circuit 11% 5 V [10 pts.] 9 A 10 20 V 6 A

help please! And can you explain me how you did it?

Answer 1

P = integral i (t) v (t) dt = Vertical-bar _0^10 (25 t) 8 + Vertical-bar _10^30 [- (25) (t - 20)] (-8) + 0 + Vertical-bar _40^60 [(25) (t - 50)] (8) + 0 = 200 times t^2/2 Vertical-bar _0^10 + 200 [t^2/2 - 20t]_10^30 + 200 [t^2/2 - 50 t]_40^60 \r\n P = 200 [[(100)^2/2 - 0] + (30)^2/2 - 10^2/2 - 600 + 200 + 60^2/2 - 40^2/2 - 3000 + 2000] = 200 [50 + 900 - 100 + 3600 - 1600/2] -1400 = 200 [2800/2 - 1400 + 50] = 10,000 Therefore P = 10,000 m^2 w = 10,000 times (10^-3)^2 W = 10^2 w = 0.01 w \r\n Energy in 60 ms = P times 60 ms = 0.01 times 60 times 10^-3 = 6 times 10^-4 J V_0 = 5V from circuit -V_g + V_a = V_0 -V_g + V_0/10 = V_0 Because V_0 = V_a V_g = V_0/10 - V_0 V_g = 5/10 - 5 V_g = -4.5 \r\n i_t = 6 + 9 i_t = 15 Amps