Question
Eleterical circuts 11th edition
Current (mA) Voltage (kV) Element -250 -3 a -400 4 b 400 1 150 1 -4 200 e f 4 50 1.32 The current and power for each of the i


Figure P1.32 ia a + Vf ic f ic 0.0 it g www + Ve d Vd b id
TABLE P1.32 Element Power (mW) Current (mA 175 25 b 375 75 150 -50 -320 40 160 20 120 f -30 55 -660
Current (mA) Voltage (kV) Element -250 -3 a -400 4 b 400 1 150 1 -4 200 e f 4 50 1.32 The current and power for each of the interconnect- ed elements in Fig. P1.32 is measured. The values are listed in Table P1.32. a) Show that the interconnection satisfies the power check. b) Identify the elements that absorb power. c) Find the voltage for each of the elements in the interconnection, using the values of power and current and the voltage polarities shown in the figure.
Figure P1.32 ia a + Vf ic f ic 0.0 it g www + Ve d Vd b id
TABLE P1.32 Element Power (mW) Current (mA 175 25 b 375 75 150 -50 -320 40 160 20 120 f -30 55 -660
0 0
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Answer #1

a)

Take the sum of the power = 175+375+150-320+160+120-660 = 0

The sum of the power is zero, so the circuit is power balanced.

b)

The particular element is absorbing power when the current is entering the positive voltage terminal of the element or current is leaving negative voltage terminal of the element.

The particular element is delivering power when current is leaving the positive voltage terminal of the element or current is entering negative i_a is entering +ve of a, so element is absorbing power.e voltage terminal of the element.

in figure current i_a is entering +ve of a, so element is absorbing power.

i_b is entering +ve of v_b, so element is absorbing power.

2. is leaving +ve of v_c, so element is delivering power.

2 is entering -ve of v_d, so element is absorbing power.

2, is entering -ve of v_e, so element is absorbing power.

2, is entering -ve of v_d, so element is absorbing power.

i_f is leaving -ve of v_d, so element is absorbing power.

2 is entering -ve of v_d, so element is absorbing power.

c)

7V Ud.

Vh7V

v_c =150V

v_d =-8V

v_f =-4V

v_g =-12V

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