Question

Calculate the standard free energy for the reaction given 1. 2 CH3OH(D +3 02(g) 2 CO2(g) 4 H20(0 AG fkJ/mol -166.4 0.0 Specie
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Answer #1

Consider a reaction : 2 CH3OH (l) + 3 O 2(g)  media%2F994%2F99410c8e-fbf5-4254-b2d0-41 2 CO 2(g) +4 H2O(l)

For above reaction , media%2Fd4b%2Fd4bf1a2c-7573-4f0a-be21-e5G 0rxn = Sum of media%2F9ed%2F9edc96a7-2a34-4dae-9a3a-17G 0f ( products ) - sum of media%2Fc80%2Fc808f0b6-42af-4382-b61d-d2G 0f ( Reactants)

=2 x media%2F7c7%2F7c7ac1f2-c608-4834-ade5-e0G 0f CO 2(g) +4 x  media%2F7bd%2F7bdcc248-0f0d-4908-be12-8eG 0f H2O(l)  - [2 x media%2F2c6%2F2c648da3-32dc-4009-81ce-c3G 0f CH3OH (l) + 3 x media%2F8cd%2F8cd201c3-9cf2-4971-84c6-47G 0f O 2(g)  ]

=(2 x -394.4 ) + ( 4 x -237.2) - [ ( 2 x -166.4 ) + ( 3 x 0.000) ]

= -1737.6 + 332.8

= - 1404.8  KJ / mol

PART 2

Consider a given reaction , B4C (s) \rightleftharpoons 4 B (g) + C (s)

For above reaction , Q =( P B ) 4  

We have relation, media%2F7c7%2F7c7ac1f2-c608-4834-ade5-e0 G = media%2F7c7%2F7c7ac1f2-c608-4834-ade5-e0G 0f +RT ln Q

= media%2F7c7%2F7c7ac1f2-c608-4834-ade5-e0G 0f + RT ln ( P B ) 4  

= media%2F7c7%2F7c7ac1f2-c608-4834-ade5-e0G 0f + 4 RT ln ( P B )

ANSWER : media%2F7c7%2F7c7ac1f2-c608-4834-ade5-e0 G = media%2F7c7%2F7c7ac1f2-c608-4834-ade5-e0G 0f + 4 RT ln ( P B )

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