Question

Be sure to answer all parts.

For an aqueous solution of sodium chloride (NaCl), determine the molarity of 3.45 L of a solution that contains 133 g of sodium chloride.

M

Determine the volume of this solution that would contain 4.73 moles of sodium chloride.

L

Determine the number of moles of sodium chloride in 22.65 L of this solution.

mol

Answer 1

I Moss of Nall = 133 gm males of ULPVV225. Nal = moss 131 gm Maloy moss 58.4 golmal = 2.28 mol os salution = 3.45 al valume 2.28 mal malority = males of Nall 3.45 L Volume of salution (2) 0.66 mal IL = 0.66M Valume of solution a matr2Bx Males of Nall .. . malority = 4.73 mal 0.66 mall = 7.17 Li - » males of Nall = malority & Valume [2] = 0.66 mal l"' x 22.654 = 14.95 mal. YIT