Solution
Answer
Explanation
in this statement x is declared and initialized to 15
so we write
x=15
but y and z not declared and initialized so we write "?"
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in this statement we declare y but not initialized so we write "*
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in this statement now we are adding value 8 to the value of x
x=15+8
x=23
y already declared, z still not declared
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now z is declared and initialized
so write 9 in z
please note y still not initialized
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now we are adding value of x and z storing in y
so y=23+9
y=32
---
all the best
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