Question

Python code to randomly select a file in a directory and then the next 9 consecutive files in the same directory

Answer 1

Python Program

#!/usr/bin/env python
# coding: utf-8

# ## Files creation

# In[55]:


# Creates 30 sample files from 0 - 30 in sample folder

for i in range(30):
    file = open("./sample/sample"+str(i)+".txt", "w") 
    file.write("Your text goes here") 
    file.close() 


# ## Select random File

# In[56]:


# import random & os package

import os, random

# select random file from sample folder

random_file = random.choice(os.listdir("./sample/"))

print("random file = ",random_file)

#list files in sample folder and stores in files

files = os.listdir('./sample/')

#prints files

print ("\nFiles        ---------------------------- \n ")
print (files)


# ## Select 9 consecutive files 

# In[57]:

# finds the random file position from files and prints next 9 files

for i in range(len(files)):
    if files[i] == random_file:
        file_position = i
        
## prints next 9 files

files[file_position+1:file_position+10]


# In[ ]:

Output