Question

Calculate the pH for each of the following cases in the titration of 50.0 mL of 0.240 M HCIO(aq) with 0.240 M KOH(aq). The ionization constant for HCIO can be found here. Number (a) before addition of any KOH Number (b) after addition of 25.0 mL of kOHD Number (c) after addition of 40.0 mL of KOH Number (d) after addition of 50.0 mL of KOH Number (e) after addition of 60.0 mL of KOH

Answer 1

aviid) deo aiial) PKa二7.53 KOH 449-14 8-765 0.31 0'= 0.012m DOO o 006 KeLo 006 No 9.6 XIo 小4x167 7-53 + 29 9.6163

E 0.012 moles 0 0la 0-0 1 oor At neunal pont 0r 12 73. 765 46 0 305 s o.305 60 al rOH X 0,240 ano /000 0 01R bone) 6o +so) 'm gola.Hơn nene 2tmauneK eeM o.oo ayre)! (Sher>> Log (0.0A,名) 14-1-66 = 1a.39 1.66 pH