Question

Instructions Part 1. Problem Solving Do all of the following: • Determine the problem statement for the following problem. • Write a set of instructions (an algorithm) for computing the required values and making the desired conclusions. • Test your instructions by hand. Show your work. Problem: The first law of thermodynamics states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system, stated mathematically as AU = Q-W where Wis the work done by the system, Q is the energy supplied to the system, and AU is the change in internal energy. A calorimeter is a device used to determine the amount of energy lost or gained during a process, often a chemical reaction. For a simple coffee cup calorimeter, a measured portion of water or ice is placed in an insulated cup, the temperature of the water is measured, and then the process is allowed to occur in the cup. The amount of energy gained or lost in the water is given by the formula Q = mwater Cwater Twater where Q is the amount of energy gained or lost, mwater is the mass of the water, water is the specific heat capacity of the water, which is 4.18 J/g/C, and AT water is the change in temperature of the water. If 100 g of water is used at a starting temperature of 20 °C, what is the amount of energy produced or absorbed by a process given that the ending temperature is a) 30 °C, b) 40 °C, C) 15 °C, and d) 10 °C.

Answer 1

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Q = mwalce water at water sTwalena Te-T, = Te-20c an Tz = 30°c Q = (100g)(4483/91°c)* ( 300-20°c) - 100x4.68XL09 = 46803 | assambed) b) T2 = 400 po 100 g) (4:18 5/9/2) (460-20°c) = 3605] (absorbed) o Te = 15°C Q = 100 x4.668 x C15°C -20°c) = 1-2 / (produced) d) Tz = Loć De 100 x 4.40 x C100-200) = -41801 (porodu ciel) of I heat expelled