Question

help me please

Q1 (10 pts) Write a java program that reads and saves 10 values from the user in an array. Then calls function smallestDistance The smallest Distance function will finds two neighboring numbers in an smallest distance to each other. The function should return the index of the first number In the sequence 4 8 6 12 9 4 the minimum distance is 1 (between 1 and 2). The function should return the index 3 (of number 1).

Answer 1

package abc;
import java.util.Scanner;

public class numberGame {
   public static int smallestDistance(int a[]) {
       int pos=0 , difference=Integer.MAX_VALUE;
       for(int i=0;i<(a.length-1);i++) {              
           if(Math.abs(a[i+1]-a[i]) < difference) { //Successively checking the distance of each element of the array with its // neighbour
               difference = Math.abs(a[i+1]-a[i]);           //if distance is lesser than previously checked elements then store the //position of this element in pos variable
               pos = i;
           }
       }
      
       return pos;
   }
   public static void main(String args[]) {
       int a[]=new int[10];
       Scanner s=new Scanner(System.in);
       System.out.println("Enter the numbers: ");
       for(int i=0;i<10;i++) {
           a[i]=s.nextInt();
       }
       int position = smallestDistance(a);
       System.out.println("\nThe position of first element with least distance neighbour is : "+position);
   }
}

For better view of the code i am uploading the image of the code in editor as well.