Question

In Java*

​​​​​​​

Write a program that reads an arbitrary number of 20 integers that are in the range 0 to 100 inclusive. The program will ask a user to re-enter an integer if the user inputs a number outside of that range. The inputted integers must then be stored in a single dimensional array of size 20. Please create 3 methods: 1. Write a method public static int countEven(int[] inputArray) The method counts how many even numbers are in the array. It takes an array as a parameter and returns the total of even numbers in the array. 2. Write a method public static int countOdd(int[] inputArray) The second method counts how many odd numbers are in the array. It takes an array as a parameter and returns the total of odd numbers in the array. 3. Write a method public static void printDividedBy5(int[] inputArray) The third method will print out all numbers that can be divided by 5 without a remainder. If there is no such number in the array, the method prints out "Good bye!". The function takes an array as a parameter and return nothing.

Answer 1

Dear student,

The solution to the above problem statement in Java programming language is given as below:

Code:

import java.io.*;

import java.util.*;

public class Main

{

public static int countEven(int[] inputArray)//calculates the total number of even integers in array

{

int count=0;//stores number of even numbers

for(int i=0;i<20;i++)

{

if(inputArray[i]%2==0)

{

count++;

}

}

return count;

}

  

public static int countOdd(int[] inputArray)//calculates the total number of odd integers in array

{

int count=0;//stores number of odd numbers

for(int i=0;i<20;i++)

{

if(inputArray[i]%2!=0)

{

count++;

}

}

return count;

}

  

public static void printDividedBy5(int[] inputArray)

{

int count=0;//stores the number of integers divisible by printDividedBy5

for(int i=0;i<20;i++)

{

if(inputArray[i]%5==0)

{

System.out.print(inputArray[i]+",");

count++;

}

}

if(count==0)

{

System.out.println("Good bye!");//prints this if no number is divisible by 5

}

}

  

public static void main(String[] args) {

Scanner sc=new Scanner(System.in);

System.out.println("Enter 20 numbers between 0 to 100 inclusive of 0 and 100");

int nums[]=new int[20];//array of integers

int space=20;

int index=0;

while(space!=0)//till there is space left in array

{

int entry=sc.nextInt();

if(entry>=0&&entry<=100)

{

nums[index]=entry;

index++;

space--;

}

else

{

System.out.println("Wrong input. Please Enter a number between 0 to 100 inclusive of 0 and 100 ");

continue;

}

}//input done

  

int numEven=countEven(nums);

int numOdd=countOdd(nums);

  

System.out.println("Number of Even integers entered: "+numEven);

System.out.println("Number of Odd integers entered: "+numOdd);

printDividedBy5(nums);

}

}

----------------------------------------------------

Output:

Enter 20 numbers between 0 to 100 inclusive of 0 and 100 20 23 111 Wrong input. Please Enter a number between 0 to 100 inclusive of 0 and 100 100 23 25 10 1 0 -1 Wrong input. Please Enter a number between 0 to 100 inclusive of 0 and 100 11 56 78 8 9 14 66 15 20 40 50 28 Number of Even integers entered: 13 Number of Odd integers entered: 7 20,100,25,10,0,15,20,40,50,

​​​​​

I hope the given solution helps clear your doubt.

Don't forget to give it a thumbs up.

Regards