2. Show that the function f:N→Q defined by f(n) = is injective but not surjective.
Prove If the functions are injective, surjective, or bijective. You must prove your answer. For example, if you decide a function is only injective, you must prove that it is injective and prove that it is not surjective and that it is not bijective. Similarly, if you claim a function is only surjective, you must prove it is surjective and then prove it is not injective and not bijective. - Define the function g: N>0 → N>0 U {0} such that g(x) = floor(x/2). You may use the fact that...
Problem 5. Determine whether each of the following function is injective and/or surjective. (a) f : R → R, f (r) = 2x – 1 (b) f : Z+ Z, f (r) = 2x – 1
Determine which of the following functions are injective, surjective, bijective (bijectivejust means both injective and surjective). And Find a left inverse for f or explain why none exists.Find a right inverse for f or explain why none exists. (a)f:Z−→Z, f(n) =n2. (d)f:R−→R, f(x) = 3x+ 1. (e)f:Z−→Z, f(x) = 3x+ 1. (g)f:Z−→Zdefined byf(x) = x^2 if x is even and (x −1)/2 if x is odd.
Problem 1.3. For each function fi, determine whether it is injective but not surjective, surjective but not injective, bijective, or neither injective nor surjective. Explain why. (1) f1: R20 + R with f1(x) = x2 for all x ER>, where R20 = {x ER|X>0} = [0, ). (2) f2: R20 + R20 with f2(x) = x2 for all c ER>0. (3) f3: R + Ryo with f3(2) = x4 for all x € R. (4) f4: R R with f4(:1)...
Consider the function f : {0,1} » N → NU{0} defined as f(x,y) = (-1)22 y. Is f injective? Surjective? Explain your answer.
Say whether the following function is injective, surjective, bijective, or none of the above (note: you can only select one option): Domain: R Codomain: (-1,1] f() = sin(x) O Surjective Bijective O None Injective
Say whether the following function is injective, surjective, bijective, or none of the above (note: you can only select one option): Domain: R Codomain: R f(x) = x3 O Injective O Bijective O None O Surjective
Say whether the following function is injective, surjective, bijective, or none of the above (note: you can only select one option): Domain: A= = {1,2,3,4,5,6} Codomain: B = {u, V, W, X, y, z} f = {(3,w), (4,2), (1,y), (6,w), (5x), (2,u)} O Bijective O Surjective Injective O None
Discrete Math 11. Consider the function f : ZZ, given by f(n) = 5n - 2. (a). Show that f is injective (namely, one-to-one). (b). Determine if f is surjective (namely, onto). Justify your answer.
4. Define a function f:N → Z by tof n/2 if n is even 1-(n + 1)/2 if n is odd. f(n) = Show that f is a bijection. 11 ] 7. Let X = R XR and let R be a relation on X defined as follows ((x,y),(w,z)) ER 4 IC ER\ {0} (w = cx and z = cy.) Is R reflexive? Symmetric? Transitive? An equivalence relation? Explain each of your answers. Describe the equivalence classes [(0,0)]R and...