Determine the soil water content in percentage by weight for a 120g sample in a moist...
Determine the soil water content in percentage by weight for a 120g sample in a moist condition that, when oven-dried, weighs 95g
What additional information do you need to determine porosity?
Homework Answers
Here given
Weight of soil in moist condition is = 120 g.
After oven dried soil weight is = 95 g.
So water present in soil = 120 - 95 = 25 g.
( Moist weight - dry weight)
In terms of percentage = (25 ÷ 120) × 100 = .20833 × 100 = 20.83%
To determine porosity , volume of total soil and particle density of soil require.
From total volume and total mass of soil we can calculate bulk density of soil.
Bulk density = total wright of soil ÷ total volume.
So porosity is = (particles density - bulk density) ÷ particles density.
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Determine the soil water content in percentage by weight for a
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please do problem 3
Problem 1: In its natural condition a soil sample has a mass of 2290 g and a volume of 1.15 x10 m. After being completely dried in an oven the mass of the sample is 2035 g. The value of G, for the soil is 2.68. Determine the bulk density, unit weight, water content. void ratio, porosity, degree of saturation and air content. Problem 3: A soil specimen is 38 mm in diameter and 76 mm...
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2. A 1.5 m3 sample of moist soil weights 2750 kg. The water content is 15.5%. Assume Gs 2.7. With this information, fill in all the blanks on the phase diagram. Also provide the void ratio, porosity and dry density. Show all your calculations Weight Volume Water Solid Air
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the only question to answer are
2-5
2-7
2-10
2-17
2-19
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