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Imagine that you are in a car that is traveling up a bridge that is inclined...

Imagine that you are in a car that is traveling up a bridge that is inclined at an angle of 14.5 degrees from the horizontal. The car's speed is 34.0 mi/hr (15.20 m/s). At time t = 0 you open your window and illegally drop a soda can from your rest frame over the edge of the bridge. Your height above ground level is 85.0 m.

How far does the can travel horizontally before hitting the ground? Neglect air resistance.

At what angle does the can strike the ground (in degrees)? This is the angle which the can's velocity vector makes with the horizontal just before hitting the ground.

What is the speed of the can just before it hits the ground?

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Answer #1

go of soda soda r t-ta0 veloel+y -H a o.thut an u sc-n,fo uS 2. -25 15.25-445) t- V - 1013 mlskindly give rating

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