Question

At a height h = 44.0 m above the ground a rocket is fired at an initial speed v0 = 168.0 m/s at an angle θ = 27 degrees above the horizontal. Ignore air resistance. The magnitude of the gravitational acceleration is 9.8 m/s2. Choose the RIGHT as positive x-direction. Choose UPWARD as psotitive y-direction. Keep 2 decimal places in all answers

(a) Find v0x, the x component of the initial velocity (in m/s)

(b) Find v0y, the y component of the initial velocity (in m/s)

(c) What maximum height (in meters) does the rocket reach above the ground?

(d) How long (in seconds) does it take the rocket to reach the maximum heght?

(e) How long (in seconds) is the rocket in the air before hitting the ground? Note: here the total time in air is ≠ twice the time to reach max height To solve for the total time in air, you need to set up a quadratic equation of time t. In general there are two solutions.

-Positive and Negative solution

(f) What is the range R (the horizontal distance) (in meters) traveled by the rocket before hitting the ground?

(g) What is the vertical component of the velocity (in m/s) just before the rocket hits the ground? Pay attention to the direction (the sign).

(h) What is the magnitude of the velocity (including both the horizontal and vertical components) (in m/s) of the rocket just before it hits the ground?

(i) What is the direction of the velocity of the rocket just before it hits the ground? Report the direction by an angle COUNTERCLOCKWISE from the +x axis.

Answer 1

Please let me know if it was helpful. Thank you!