Question

The accompanying data represent the total travel tax (in dollars) for a 3-day business trip in 8 randomly selected cities. A normal probability plot suggests the data could come from a population that is normally distributed. A boxplot indicates there are no outliers. Complete parts (a) through (c) below. 68.87 78.93 69.91 84.56 79.61 87.92 101.47 98.34 Click the icon to view the table of critical t-values. (a) Determine a point estimate for the population mean travel tax. A point estimate for the population mean travel tax is $ (Round to two decimal places as needed.) (b) Construct and interpret a 95% confidence interval for the mean tax paid for a three-day business trip. Select the correct choice below and fill in the answer boxes to complete your choice. (Round to two decimal places as needed.) O A. There is a % probability that the mean travel tax for all cities is between $ and $ O B. One can be % confident that the all cities have a travel tax between $ and $ OC. One can be % confident that the mean travel tax for all cities is between $ and $ OD. The travel tax is between $ and $ for % of all cities.

Answer 1

From the given data we have sample size M = 8 (9) sample mean (W = sta o = 83.451 = 183.457 Round decimal A point estimate for the population mean? . places travel tax =18345)

Standard deviation (5) - ELL =) Views 1168-87-834994... +(98-34-83.4539) - 112.317 ) (b) At 95% confidence interval X2 1-0-952 0.05 .01220.025 degree of freedom (df) = n1 = 8477 Bouthical = 10.025,9 2 2.365 95% confidence interval for the mean tax pard for . a three day business trip ♡ I bowticas * = 83.45 + 2-365* 12. 3117 n 383.45 + 10.294 - 73.156, 93.744 -173-16, 93.74] Round fo 2 decimas - places one can be 1954. confident that the mean travel tax for all cities os between $173.16) and $ 193.74] o

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