Question

0 **************** ********** sample of saturated clay had an initial volume of 86.2 ml and was isotro consolidated at a cell pressure of 300 kN/m, which assured normal consolidation. consolidation 6.2 ml of water was expelled into the drainage burette and the void rare sample at this stage was estimated to be 0.893. The sample was then subjected to drame and readings of deviator stress and volume change were taken at increments of axia with the following results: 5, % 0.0, ,kN/ m AV.ml - 0 0 1 5 210 2.47 10 330 5.12 15 415 6.72 20 478 7.76 22 507 8.08 Co 2.3 d 02 and c = 0.595, plot the stress path normalized to P And the stre curve,axial strain-volumetric strain relation.

Answer 1

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per atele 6.6 884 6.5 - - 10:54 2 04 06 8 10 plie VD solution. volume after consolidation = 86. 2 6 .2 = 80 me Now, volumetric strain, Ev= AV ve where Ar= change in volume, Vo= original volume, let specific volume at a particular value of volumetric strain, Eu be, Valte therefore, ev = AV = (1+e)-(ite.) = vavo Volte, :v=voll-eo) . Now, le = CN-V) [This formula is from the whered slope of normal compression - Line. Let us make a taste Ea ca-Erlor Ev v re ' I l /pel alre O O 1.893 300 300 to s 210 247 0.0311-834 49.1 370 6.89 0:503 15.12 0.064 1.772 588.6 410 o.fo u15 16.72 0.084 1.734727.0 438.3 0.60 20 478 17.76/0.097 1.709 835.3 459. 3 o.ss. 22 507 1808 0-1011-702 |8c8-44490 0:54 | 054