Question

A solid ball has a radius of 2.50 cm and a charge of 8.33 uc Part(a) If the ball is made from a conducting material, calculate the electric field in N/C) at a point that is ri - 3.85 cm from the center of the ball. Numeric : A numeric value is expected and not an expression. E = Part (b) If instead the ball is made from a non-conducting material and the charge is spread evenly through the ball, calculate the electric field in N/C) at a point that is ri= 3.85 cm from the center of the ball. Numeric : A numeric value is expected and not an expression. E= Part (e) If the ball is made from a conducting material, calculate the electric field in N/C) point that is r2 -1.63 cm from the center of the ball. Numerie : A numeric value is expected and not an expression. E- Part (d) If instead the ball is made from a non-conducting material and the charge is spread evenly through the ball, calculate the electric field in N/C) at a point that is r - 1.63 em from the center of the ball. Numerie : A numeric value is expected and not an expression. E-

Answer 1

Parta given that nadius of the ball, R=2.5cma 2.5*10m e. Change on it, Q = 8.33mc = 8.33 xiños field Point is at, n, 23.85cm = 3.85*10m so, electric field there will be 47t, 3) E= ax 109 x 8. 33x106 (3.85 +1022 35 t1022 Nie - LE = 50578512.4 Nic ,

part-b If the ball is made of non-condueting material, then also, the electric field at B, will be same as before ie, E = Antinh since it acts Placed at for any s>r(badius) line a point Change its center. 3,1 E = 50578512.4 NIC Part -C Now, ginen, nq = 1.63cm<r so, the point is on the .. buik matenial of the Condueting ball. Since under electrostatic condition Eelectric field inside a

Conductor is zero. so. Part -d we know that for a non Conducting ball, which is uniformly Charged with Change density - the electric field en the PE 42 7R3, distance the the inside cap' from at in sphere center Q R .. 1 E= pr - . = ARR3 st. E = ADE. R² 1630 Pa 1.63 ( - E = 8.33*10 9710 x 1,630102 (2.3x102) NC » 1E= 78 208704 NIC 1