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Newtonian) The following shear stress-shear rate data were obtained on a 6 wt% solution of sodium cellulose sulfate polymer i

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Answer #1

Part a.

The plot of Log(shear stress) vs Log(shear rate) can be drawn as follows.

Log(Shear stress) 1.5 2.0 0.5 1.0 Log(Shear rate)

The equation of the plot: Log(Shear stress) = 0.50697*Log(Shear rate) + 1.24333

Part d.

If shear rate = 5000 s-1, Log(Shear rate) = Log(5000) = 3.69897

i.e. Log(Shear stress) = 0.50697*3.69897 + 1.24333

i.e. Log(Shear stress) = 3.1186

Hence, the shear stress or viscosity = 1314.0044 Pa

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