Question

As shown in the figure below, a projectile is fired horizontally with a speed of 30 m/s from the top fa cliff 80 m high. (a) How long will it take to strike the level ground at the base of the cliff? (b) low far from the foot of the cliff will it strike? (c) With what velocity will it strike? (20 Points). 0-30 ms 80 m 30 m/s 40 m/s

Answer 1

Solution Given that - Ya Ug = 30 m/s lai v; = 30 m/s Bom > Strike the level. ground at the base of clif to be find? • Take y-axis ay = Voy t + 1/ s gyte In Given data ay :-90 Yoy = 0 & ay = 9 --9.8, mis ау. , y + + + 9,4* - 80 = o(t) + 1 / 2 (-981) t² 7 80 = 49.81 (t") 80 = 4.905(6) t=516.309

(6) To find How for from the foot of the cliff to it Strike. na vext v; = 30 mis t: 4.03 X: 30 x 4.03 (n = 120.9) Velocity will it strike to be find. Where Y = Up = 30m/s Vy Yoy(t) + gy(t) °. 0(t) +(-9.80(4.03) Vy = - 39.53) var ve bu vya =>/ (30)2+(-39.53) Tomb 1900 + 1562.6 v2462.6 find o L= 49.62 mis tan o tano = 39,53 = 1:31 1052.9°) 30
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