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Questions 6-10: Prior to execution of the instruction MOV CX,[1234H) - following are the information given...
Anyone explain to (i), (ii) How can we get the instruction words and R8=?[hex]? (i) instruction...
Anyone explain to (i), (ii)
How can we get the instruction words and R8=?[hex]?
(i) instruction words[hex] is 0x4508, and R8= 0xF002
How can I get that?
(ii) instruction words[hex] is 0x4548 and R8=0x0002
How can I get that?
Consider the following instructions given in the table below. For each instruction determine its length (in words), the instruction words (in hexadecimal), source operand addressing mode, and the content of register R7 after execution of each instruction. Fill in the empty...
Using the register and data memory contents listed in the table below, after executing the instruction:...
Using the register and data memory contents listed in the table
below, after executing the instruction:
mov.b WREG,
0x1001
What are the contents of 0x1000?
Using the register and data memory contents listed in the table
in Q7, after executing the instruction:
mov #0x1001, W0
What are the contents of 0x1000?
7. Using the register and data memory contents listed in the table below, after executing the instruction: mov.b WREG, Ox1001 What are the contents of Ox1000? ANSWER: Data Memory...
위8원의 12 55 56 91 A1 B1 C1 B1 00 01 02 UXU303 Ox0210 Ox0214 Ox0218...
위8원의 12 55 56 91 A1 B1 C1 B1 00 01 02 UXU303 Ox0210 Ox0214 Ox0218 Ox021C 40 Ox0302 Ox0301 Ox0300 30 20 D1 D2 D3 D4 D5 D6 D7 D8 10 The following MSP430 memory system consists of 2 consecutive 64-Byte RAM chips starting at location ox200, and 512 Byte of Flash ending at 0XFFFF. Fill in the blanks (4) with the correct starting or ending addresses. C Starting Address Starting Address Ending Address (Binary) (Hex) (Hex) 64B RAM1...
MULTIPLE CHOICE!! If register t0 contains 0 and t1 contains 4, what would the following instruction...
MULTIPLE CHOICE!! If register t0 contains 0 and t1 contains 4, what would the following instruction do? (MIPS) sw $t0, 0($t1) A. Load 4 into register t0 B. Load 0 into register t1 C. Copy the content at memory address, 4, into register t0. D. Copy the contents at memory address, 0, into register t1. E. Copy the contents of register t0 into the memory address, 4. F. Copy the contents of register t1 into the memory address, 0.
Examine the following code and answer the following: 10. Register contents after execution of each instruction Machine code using hand assembly EDSIM51 Simulation a. b. c. istart (origin) at 0 ;l...
Examine the following code and answer the following: 10. Register contents after execution of each instruction Machine code using hand assembly EDSIM51 Simulation a. b. c. istart (origin) at 0 ;load 25H into R5 iload 34H into R7 ;load 0 into A ;add contents of R5 to A now A-A+R5 ; add contents of R7 to A inow A A+R7 ;add to A value 12H ORG OH MOV R5,#25H MOV R7 , #34H MOV A, #0 ADD A, R5 ADD...
2. After initialization a user executes the following instructions: ORGO 0000 MOV A, #30H 0002 PUSH...
2. After initialization a user executes the following instructions: ORGO 0000 MOV A, #30H 0002 PUSH A 0003 LCALL 0500H 0006 .. What are the contents of memory locations 8, 9 and 10 after the LCALL? (A) OSH OOH 30H (B) 30H OOH O5H (C) 30H 06H OOH (D) none of the above 3. If in question #2 a RET instruction is assembled and located at 0500H. The next instruction executed after this RET will be the instruction at memory...
(2+2+1 5 points) Problem 10.1: simple cpu machine code = The following program has been written...
(2+2+1 5 points) Problem 10.1: simple cpu machine code = The following program has been written for the simple central processing unit introduced in class. The table below shows the initial content of the 16 memory cells. The first column denotes the memory address. Machine Code Assembly Code Description 001 1 0001 0 010 0 1111 1 001 1 0000 3 101 1 0100 110 1 0110 4 111 1 0000 5 6 001 0 001 1 100 1 0001...
Instruction set architecture R: register X, Y, Opl, Op2: Operand Quantity: constant value EA: Effective memory address Opcode Operation Name MOV X, Y XCH Opl, Op2 ADD X, Y SUB X,Y SAL Op, Quantity...
Instruction set architecture R: register X, Y, Opl, Op2: Operand Quantity: constant value EA: Effective memory address Opcode Operation Name MOV X, Y XCH Opl, Op2 ADD X, Y SUB X,Y SAL Op, Quantity SAR Op, Quantity Shift Arithmetic Right on Op for Quantity SHR Op Quanti AND X, Y OR X, Y XOR X, Y NOT X LOADR, A LOAD R, (A STORE R, A STORE R, (A Description Move data from Y to X Exchange Op1 with Op2...
Need help on Assembly language 1.Solve the following conditions: A. Suppose AL contains 11001011 and CF...
Need help on Assembly language 1.Solve the following conditions: A. Suppose AL contains 11001011 and CF = 1. Give the new contents of AL after each of the following instructions is executed. Assume the above initial conditions for each part of this question. a. SHL AL,1 b. SHR AL,1 c. ROL AL,2 d. ROR AL,3 e. SAR AL,2 f. RCL AL,1 g. RCR AL,3 B. Suppose EAX contain ABCDH. Show the contents of BX and CX after...
A C program has been compiled into the Atmel AVR assembly language. The following instruction, which...
A C program has been compiled into the Atmel AVR assembly
language. The following instruction, which is located at address
0x002A, is executed:
i.) What is the binary value contained in the instruction
register (IR) when the instruction is executed?
ii.) What is the hexadecimal value of the program counter (PC)
when the instruction is executed?
iii.) If register r1 = 0x40 and register r2 = 0x02 prior to
executing the instruction, what are the contents of r1 and r2...
Anyone explain to (i), (ii)
How can we get the instruction words and R8=?[hex]?
(i) instruction words[hex] is 0x4508, and R8= 0xF002
How can I get that?
(ii) instruction words[hex] is 0x4548 and R8=0x0002
How can I get that?
Consider the following instructions given in the table below. For each instruction determine its length (in words), the instruction words (in hexadecimal), source operand addressing mode, and the content of register R7 after execution of each instruction. Fill in the empty...
Using the register and data memory contents listed in the table
below, after executing the instruction:
mov.b WREG,
0x1001
What are the contents of 0x1000?
Using the register and data memory contents listed in the table
in Q7, after executing the instruction:
mov #0x1001, W0
What are the contents of 0x1000?
7. Using the register and data memory contents listed in the table below, after executing the instruction: mov.b WREG, Ox1001 What are the contents of Ox1000? ANSWER: Data Memory...
위8원의 12 55 56 91 A1 B1 C1 B1 00 01 02 UXU303 Ox0210 Ox0214 Ox0218 Ox021C 40 Ox0302 Ox0301 Ox0300 30 20 D1 D2 D3 D4 D5 D6 D7 D8 10 The following MSP430 memory system consists of 2 consecutive 64-Byte RAM chips starting at location ox200, and 512 Byte of Flash ending at 0XFFFF. Fill in the blanks (4) with the correct starting or ending addresses. C Starting Address Starting Address Ending Address (Binary) (Hex) (Hex) 64B RAM1...
Examine the following code and answer the following: 10. Register contents after execution of each instruction Machine code using hand assembly EDSIM51 Simulation a. b. c. istart (origin) at 0 ;load 25H into R5 iload 34H into R7 ;load 0 into A ;add contents of R5 to A now A-A+R5 ; add contents of R7 to A inow A A+R7 ;add to A value 12H ORG OH MOV R5,#25H MOV R7 , #34H MOV A, #0 ADD A, R5 ADD...
2. After initialization a user executes the following instructions: ORGO 0000 MOV A, #30H 0002 PUSH A 0003 LCALL 0500H 0006 .. What are the contents of memory locations 8, 9 and 10 after the LCALL? (A) OSH OOH 30H (B) 30H OOH O5H (C) 30H 06H OOH (D) none of the above 3. If in question #2 a RET instruction is assembled and located at 0500H. The next instruction executed after this RET will be the instruction at memory...
(2+2+1 5 points) Problem 10.1: simple cpu machine code = The following program has been written for the simple central processing unit introduced in class. The table below shows the initial content of the 16 memory cells. The first column denotes the memory address. Machine Code Assembly Code Description 001 1 0001 0 010 0 1111 1 001 1 0000 3 101 1 0100 110 1 0110 4 111 1 0000 5 6 001 0 001 1 100 1 0001...
Instruction set architecture R: register X, Y, Opl, Op2: Operand Quantity: constant value EA: Effective memory address Opcode Operation Name MOV X, Y XCH Opl, Op2 ADD X, Y SUB X,Y SAL Op, Quantity SAR Op, Quantity Shift Arithmetic Right on Op for Quantity SHR Op Quanti AND X, Y OR X, Y XOR X, Y NOT X LOADR, A LOAD R, (A STORE R, A STORE R, (A Description Move data from Y to X Exchange Op1 with Op2...
A C program has been compiled into the Atmel AVR assembly
language. The following instruction, which is located at address
0x002A, is executed:
i.) What is the binary value contained in the instruction
register (IR) when the instruction is executed?
ii.) What is the hexadecimal value of the program counter (PC)
when the instruction is executed?
iii.) If register r1 = 0x40 and register r2 = 0x02 prior to
executing the instruction, what are the contents of r1 and r2...
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