Question

Create a function named build_letter_distribution that has the same signature as build_dictionary. This function returns a dictionary; however, each key will be a letter and the value will be the count that represents how many times that letter was found. Essentially you will have a letter distribution over a sentence (which is a list of words). The letters should be case insensitive. See the lesson on "Working with Lists" on how to get the individual characters from a string Normalize letters by using the lower case (see the 'kitchen sink' lesson)

def build_word_counter(string): d = dict() for x in string: x = x.lower() if not d.get(x): d[x] = 1 else: d[x] += 1 return d

It did not past the test, saying that Traceback (most recent call last): File "/home/runner/unit_tests.py", line 159, in test_build_letter_distribution self.assertEquals(solution3, ans3) AssertionError: {'i': 5, 'l': 5, 'k': 4, 'e': 5, 'd': 10, '[73 chars]': 1} != {'I': 38, 'LIKE': 19, 'Dogs': 152, 'Black':[81 chars]: 19} + {'All': 19, - {'a': 4, - 'b': 2, - 'c': 1, - 'd': 10, ? ^ + 'Bad': 19, ? ++ ^ + 'Black': 19, + 'Dogs': 152, + 'Green': 19, - 'e': 5, - 'f': 1, - 'g': 9, - 'i': 5, - 'k': 4, - 'l': 5, - 'm': 1, - 'n': 3, ? ^ + 'I': 38, ? ^ + + 'LIKE': 19, + 'Mean': 19, + 'kinds': 19, + 'like': 19, - 'o': 9, ? ^ + 'of': 19} ? + + ^ - 'r': 1, - 's': 9}

Answer 1

The reason why your code is not working is because input to the function is a list of words and not a word. Your loop only traverses through the list and not each character inside the word. You need to add another loop inside the current loop to traverse through each letter inside the word.

Code:

def build_letter_distribution(string):

    d = dict()

    for x in string:

        for i in x.lower():

            if not d.get(i):

                d[i] = 1

            else:

                d[i] += 1

    return d

print(build_letter_distribution(["Like","test","DOGS"]))

Output:

def build_letter_distribution(string): d = dict() for x in string: for i in x.lower(): if not d.get(i): d[i] = 1 else: d[i] += 1 return d print(build_letter_distribution(["Like","test", "DOGS"])) {'l': 1, 'i': 1, 'k': 1, 'e': 2, 't': 2, 's': 2, 'd': 1, 'o': 1, 'g': 1}