Question

12. Prove the following properties of Boolean algebras. Give a reason for each step. a. (x + y x) b. x.(z+y) + (x + y) = x

0 0
Add a comment Improve this question Transcribed image text
Answer #1

a)

(x+y.x)'

=x'.(y.x)' (demorgan's law)

=x'(y'+x') (demorgan's law)

=x'.y'+x'.x'(distributive law A.(B+C)=A.B+A.C)

=x'.y'+x' (Idempotent law A.A=A)

=x'+x'.y' (Commutative law)

=x' (absorption law A+AB=A where A=x', B=y')

b)

x.(z+y)+(x'+y)'

=x.z+x.y+(x'+y)' (distributive law)

=x.z+x.y+(x')'.(y') (demorgan's law)

=x.z+x.y+x.y' (double negation law (A')'=A)

=x.z+x.(y+y') (distributive law)

=x.z+x.1 (complement law A+A'=1)

=x.z+x

=x+xz

=x (absorption law)

c)

(x.y)'+x'.z+y'.z

=x'+y'+x'z+y'.z (demorgans law)

=x'+y'+z.(x'+y') (distributive law)

=x'+y'+(x'+y').z (commutative law)

=x'+y' (absorption law A+AB=A where A=x'+y' B=z)

Add a comment
Know the answer?
Add Answer to:
12. Prove the following properties of Boolean algebras. Give a reason for each step. a. (x...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT