Question

Required information A chemist made six independent measurements of the sublimation point of carbon dioxide (the temperature at which it changes to dry ice). She obtained a sample mean of 196.64 K with a standard deviation of 0.69 K. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Use the Student's t distribution to find a 98% confidence interval for the sublimation point of carbon dioxide. (Round the final answers to two decimal places.) The 98% confidence interval is ,

Answer 1

Date Page. Solution, - Given that, X = 196.64 6 = 0.69 n = 6 At 98 o confidence level, 2=1- 98 olo A =1- 0.98 = 0.02 ✓ = 0.02 = 0.01 Zx12= 20.01 - 2.326 0.01 of error = = Z2/2 X 6 un E = 20320 x 0-69 E- 0.66 At 98 % confidence interval. X - ECM X te 196.64 - 0.66 ces <196.64 +0.66 195.98 << 197.30 (195.98,197.30) The 98 do confidence intervalis (195.98], 197.30