Question

developing involves ut from a file a person's first name, last name, phone number and birth a menu driven database application. You need to 4) This program accept as input ogram will be menu driven with the following options: 1) Find a person's information 2) Add a person to the database 3) Edit a person's information 4) Display all records to the screen 5) Quit Option 1 allows the user to enter a name after which you will search for and display the person's information. Use the binary search algorithm discussed in this chapter. Option 2 allows the user to add a person to the database. Option 3 allows the user to change any information related to a specific individual. Be careful, if the user changes the last name of the person, the arrays will need to be resorted. . Option 4 displays to the screen all of the records sorted by last name in the data e Option 5 will end the program. The data will be read from the file only once, and will only update the file affer the base. 407

C++

Answer 1

#include<iostream.h>
int i=0;
int count;
struct Person
{
char fname[30];
char lname[20];
char ph[10];
char dob[10];
}p[20];
void addperson()
{
//reading details of the person
cout<<"Enter firstname";
cin>>p[i].fname;
cout<<"Enter lasname";
cin>>p[i].lname;
cout<<"Enter phone number";
cin>>p[i].ph;
cout<<"Enter Date of birth(DD-MM-YYYY)";
cin>>p[i].dob;
i=i+1;
count=i;
}
void display()
{
// displaying person details
int k;
cout<<"\n Person Details";
for(k=0;k<count;k++)
cout<<"\n Firstname:"<<p[k].fname<<"\n Last name:"<<p[k].lname<<"\n Phone number:"<<p[k].ph<<"\n Date of birth:"<<p[k].dob;
}
void editperson()
{
// modifying the person name
int ch,k;
char name[30],edit[30];
cout<<"Enter name";
cin>>name;
for(k=0;k<count;k++)
{
if(p[k].fname==name)
{
cout<<"\n1. First name.\t 2. Last name.\t 3. Phone number.\t 4. Date of birth";
cin>>ch;
switch(ch)
{
case 1: cout<<"enter firstname";cin>>p[k].fname; break;
case 2: cout<<"enter lastname";cin>>p[k].lname;break;
case 3: cout<<"Enter phone number";cin>>p[k].ph;break;
case 4: cout<<"Enter Date of birth(DD-MM-YYYY)";cin>>p[k].dob;break;
default: break;
}
}
break;
}
}
void findperson()
{
char name[30];
int k;
cout<<"Enter name of the person";
cin>>name;
for(k=0;k<count;k++)
if(p[k].fname==name)
{
cout<<"firsname:"<<p[k].fname;
cout<<"\n lastname:"<<p[k].lname;
cout<<"\n phone number:"<<p[k].ph;
cout<<"\n Date of birth:"<<p[k].dob;
}
else
{
cout<<"\n Person not found";
}
}

void main()
{
int n;
cout<<"\n 1. Find Person.\n 2. Add Person\n 3. Edit Person\n 4. Display.\n 5. Exit";
cin>>n;
do
{
switch(n)
{
case 1: findperson();break;
case 2: addperson();break;
case 3: editperson();break;
case 4: display();break;
case 5: break;
}
}while(n!=5);
}