please prove part (b) use complex analysis and calculus of residue
The last equation in first page is equation number (4).Finally we consider as R tends to infinity because we choose the radius R arbitrarily.
please prove part (b) use complex analysis and calculus of residue -dx neif a> 0 5....
(b) For any real number a > 0, O COS X dx = te /a. x2 + a? - [Hint: This is the real part of the integral obtained by replacing cos x by eix]
Evaluate the following integral using residues: cos(bx)-cos(ax) I = dx. x2 Let a and b: real constants such that a > b >0. Note: cos(bz)-cos(az) has a singularity at z = 0 is removable, z2 ejbz-ejaz has a pole at the origin. Make sure to handle this point correctly 22
Use the residue theorem to compute the next definite integral please don't skip any steps and answer thoroughly cos(a.x) som (a > 0, b>0). (22 +62)2d.t
please 2 only, thanks Exercises dA (1) Use Cauchy's residue theorem to compute Jo 2+sin (2) Repeat the preceding exercise for 8" 131. (3) Let a be a complex number such that lal < 1. Prove that (2 27 Jo 1 - 2a cos 0 + a2d6 = 1 - 22 (4) What is the value of the integral in the preceding exercise when |al > 1? (Hint: Let b= 1.)
complex analysis onus: Prove that/sin(H)dr=「cos(r2)dr= 0 Hint: Use a closed sector contour as in the previous exercise, but with angle instead. The value of the Gaussian integral will prove useful as well! onus: Prove that/sin(H)dr=「cos(r2)dr= 0 Hint: Use a closed sector contour as in the previous exercise, but with angle instead. The value of the Gaussian integral will prove useful as well!
Evaluate the following integral using residues: I = { cos(bx)-cos(ax) dx. x2 Let a and b: real constants such that a > b>0. Note: cos(bz)-cos(az) is well-behaved along the real axis (singularity at z = 0 is removable), ejbz-ejaz has a pole at the origin. Make sure to handle this point correctly 22
find the indefinite integral and check the result by differentiation Analytic Geometry & Calculus II, Final Examination Part I, Spring costx)swLx) b) J sin 2x cos 2x dx 2 (-cos (4)(Hx) check. (x-5)=2 xs_6x-20 dx Analytic Geometry & Calculus II, Final Examination Part I, Spring costx)swLx) b) J sin 2x cos 2x dx 2 (-cos (4)(Hx) check. (x-5)=2 xs_6x-20 dx
use all 3 cases please 0. Prove that for every real number x, if -3| > 3 then x2 > 6x. Proof: Given |x - 3]> 3.
Hi, I really need help on both parts of this complex analysis question. Thanks! 1. Let be a complex number and let 12=C 1.R>o be the complement in C to all real positive multiples of . (a) Show that the function 2 H 23 has a continuous inverse function, called 37, on N. (Hint: polar coordinates might help). Prove that there are exactly three different such continuous functions. Deduce that there is no continuous extension of 37 on all of...
10. Let and consider approximating its average value on the interval (0,2) given by the integral 4-2 dx. 0 (a) Use Calculus to show that the the exact answer is π/2. (Hint: You may want to substitute 2 sin , and later use the trignometric identify cos(20)-1-2 cos2 θ). (b) Assume r is uniformly distributed in (0,2). What is the expected value, E f ()] How is the formula for expected value related to the expression given by expression in...