Question

1.03. An average interior temperature test of a sample with 15 observations of a material used as building material resulted in sample mean 20.596. Assume that melting point is normally distributed with sample standard deviation of 2.2. Test the hypotheses if true mean is less than 22.2 at the 1% significance level and find bounds for P-Value.

Answer 1

Hoill = 22.2 H,:4 < 22.2 I left teiled text I ne seviled dead na 15, 8 = 20.596,5=22, 2=0.0|| Population standard deviation is unknown so we use the to distribution, Test Statistic, t- -4 sin 20.596-22.9 2.215 -1.604 , -=-2,82375 = 0.568038 ܐ ܙ ܐ ܙ t= -2.824 P- balue = Po (t < -2.894) I df = -1 = 15-1 = 10:0068 pusing P-cailee? ! -14 | alculator J The result is significant at Péd=0:01 Since, P-value is less than the d=0:01 So, (we Reject the hall hypothesis Conclusion Į There is Q=0.01 sufficient evidence to support the claim at level of Sgmificance.