Question

*Requires use of SPSS*

1. A researcher is interested to learn if the level of interaction a women in her 20s has with her mother influences her life satisfaction ratings. Below is a list of women who fit into each of four levels of interaction. Conduct a One-way ANOVA on the data to determine if there are differences between groups; does the level of interaction influence women’s ratings of life satisfaction? Report the results of the One-way ANOVA. If significance is found, run the appropriate post-hoc test and report between what levels the significant differences were found. Report the test statistic using correct APA formatting and interpret the results.

No Interaction	Low Interaction	Moderate Interaction	High Interaction
2	3	3	9
4	3	10	10
4	5	2	8
4	1	1	5
7	2	2	8
8	2	3	4
1	7	10	9
1	8	8	4
8	6	4	1
4	5	3	8

Answer 1

To test the hypothesis is that at least one of the mean ratings of life satisfaction is different among four interaction groups at 5% level of significance. The null and alternative hypothesis is, H:14 = 12 = Ils = 14 H.: at least one 14 is unequal. The F-test statistics is, By using SPSS software, find F-test statistics with the help of following steps: Import the data Click Analyze. Choose One-Way ANOVA from Coinpare Means. Add Dependent Variables and Factors. Click Ok. 3) ANOVA Ratings Sum of Squares Sia .311 1.236 Between Groups Within Groups Total 10.252 8.295 290.322 321.077 From the SPSS output, the F-test statistics is 1.24 The p-value for this test is, From the SPSS output, the p value for this test is 0.311 . Decision The conclusion is that p-value in this context is higher than 0.05 which is 0311, so the null hypothesis is not rejected at 5% level of significance. There is insufficient evidence to indicate that at least one of the mean ratings of life satisfaction is different among four interaction groups. The result is not statistically significant. The post-hoc is not possible due to the mill hypothesis is not rejected.