Question

Q1# THE POSITIO OF A PARTICLE MOVING A LONG X-axis is given by: 3 X= 3ť + 6 + 5 Where x in meters and t in seconds. 1- What is the average velocity between the time interval from t =2s to t = 4s? 2- Find the velocity at t =3s ? 3- Find the acceleration at t =3s?

Answer 1

= 24 X 4-2 Solection) X = 3t² +64 +5 (1) Average velocity between t=2s to t=4s X(t=2s) = 3 (2) 3 + 6(2) +5=41. X (t=us) = 3 (4)3 + 6(4) + 5 = 221 Average velocity, Varg - x (t = 48) - 4-2 Varg = 221-41 - 90 Varg = 9 Juils (2) velocity at t=38, V = ? V = dx = a ( 3t² + 6 + + 5) V= 3(3) (+²) +6 = 9+² +6 ult=3s) = 9 (3)² + 6 = 87. vlt=3s) = 87 v=87 ml at dt (3) acceleration, az? at t=35 dt it. alde (92+6) - ()+d (6) an 9(2+) = 18t = 18x3 = 54