x = 14t^2 - 5 t^3
v = 28t - 15t^2
a = 28 - 30t
part a
position at t= 6s => x =-576m
as I can see you have solved till part g
so now part h
at the instant particle is not moving ,,,,,so v = 0
we get v= 28t - 15t^2 = 0
t = 28/15 s = 1.8666 s
so at t = 1.8666s we have a = 28 - 30*1.8666 = -28 m/s2
part i
avg vel between t = 0 and t = 6s
avg vel = displacement / time
at t = 0........ x = 0 m
at t = 6s.........x = -576m
so displacement = -576m
avg vel = -576 / 6 = -96m/s
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