Solution:
Given that n = 247, r = 60
The sample proportion is,
p̂ = r/n = 60/247 = 0.2429
The level of significance is α = 0.1
Test Hypotheses:
H0: p ≥ 0.301
H1: p < 0.301
test statistic z = p̂ - p/sqrt(pq/n)
= (0.2429-0.301)/√[0.301(0.699)/247]
= -1.99
P-value = P(z< -1.99) = 0.0233
A. The P-value is less than the level of significance so the data are statistically significant. Thus, we reject the null hypothesis.
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Points out ofs.eo Not yet answered P Flag question Benford's Law claims that numbers chosen from very large data files tend to have "1" as the first nonzero digit disproportionately often. In fact, research has shown that if you randomly draw a number from a very large data file, the probability of getting a number with "1" as the leading digit is about 0.301. Suppose you are an auditor for a very large corporation. The revenue report involves millions of...
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