Question

A teacher wants to see if a new unit on factoring is helping students learn. She has five randomly selected students take a pre-test and a post test on the material. The scores are out of 20. Has there been improvement? (pre-post) Student 1 Pre-test 12 12 Post- Test 15 1520 13 The test statistic equals -0.56. What would be the p-value? Op-value < 0.002 p-value > 0.10 p-value > 0.05 p-value<0.001

Please show work and/or explain why this is the correct answer.

Answer 1

Answer)

Here sample sizes are n1=n2= 5

Now as the population s.d is unknown here, we will use t table to estimate the probability

Degrees of freedom is given by smaller of n1-1, n2-1

So, here DF is 4

Now look in to the t table

For the column of 4 DF, you will see, 0.000 with probability= 0.5

And 0.741, with probability = 0.25

As 0.56 lies in between 0 and 0.741

So, p-value must lie in between 0.25 and 0.5

As 0.25 (lower value is greater than 0.1

So, P-Value > 0.1