Question

A 230,0 mL sample of a 0.275 M solution is left on a hot plate overnight the following morning the solution is 1.31 M. What volume of solvent has evaporated from the 0.275 M solution? Select one: 48.3 mL 63.3 mL 181.7 ml 230. mL 2T8 ml What mass of NaOH is required to react exactly with 25.0 mL of 28 M H2SO? Select one: 2.89 b 0.79 c 5.69 d. 1409 none of these Which of the following compounds is soluble in water? Select one: a. NI(OH)2 b. K3PO4 c Baso o d. COCO PbCl2

Answer 1

Hope you will like my answer.

1 Move My V2 (0.215M) (230.0 me) = (1-31m) Vz a = 48.28 ml - 48.3 ml : Initial volume (V.) = 230.0 ml. final volume (V2) = 48.3 ml. . Volume evaporated = ( 230.0-4803) ml = [181-7 ml mo 2. Millimoles of Hy Soy = Volume * Molarity - (25.0 x 2.8) = 70.0 m-mol .; Hy sou + 2H+ + 5042- i mno mol of H+ = (2x70) = 140 m.mol. i momol of Noot required = momol of H+ = 140. mmol = 140x10-3 mol Molar mass of NaOH = 40.0gImol i miest NaOH needed = moles x Momass =(140 x 40x10-3) : : 5.6 g @ Ics Scanned with CamScanner