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A tug-of-war game is played by five children: three on one team and two on the...

A tug-of-war game is played by five children: three on one team and two on the other. How much force will the two-child team have to exert against the three child team in order to hold the rope steady if the three children opposing them exert forces of 300 N, 150 N, and 50N respectively? Will the force be equally distributed between the two children?

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Answer #1

Let the three children team be on left side of the rope and two children team on the right side of the rope. The rope is static so the sum of net pulling force towards left (here it is 300N+150N+50N= 500N) has to be equal to the net pulling force towards right, so the two children team also exerts a net force of 500N. It's not necessary to divide the force equally between the two children but any combination of individual forces should result in the net force (their sum) equal to 500N.

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