M = 3.42
t = 1.72
sM = √(0.452/21) =
0.1
μ = M ± t(sM)
μ = 3.42 ± 1.72*0.1
μ = 3.42 ± 0.1694
90% CI [3.2506, 3.5894].
Une tho standard o mal dstritution or thtdstritution to construct a 9 con idence interval tor...
Use the standard normal distribution or the t distribution to construct a 9 % confidence interval for the population mean Justify your decision if neither distribution can be used, explain why Interpret the results ln a random sample of 17 mortgage institutions, the mean interest rate was 3.69% and the standard deviation was 36% Assume the iterest rates are normally distributed Which distribution should be used to construct the confidence interval? ○ A. Use a t-distribution because it is a...
6.2.36-1 Question Help Use the standard normal distribution or the t-distribution to construct a 95% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a random sample of 15 mortgage institutions, the mean interest rate was 3.42% and the standard deviation was 0.44%. Assume the interest rates are normally distributed Which distribution should be used to construct the confidence interval? O O O O O A. Use a...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.27. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 2.9 8.4 7.2 4.3 6.8 2.7 7.2 4.8...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.21. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 3.2 6.8 6.1 3.6 6.3 7.1 6.4 5.5...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 122. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed 22 2.9 3.9 4.6 5.5 5.5 62 75...
Use the standard normal distribution or the t-distribution to construct a 95% confidence interval for the population mean. Justify your decision. If neither distribution can In a recent season, the population standard deviation of the yards per carry for all running backs was 1.21. The yards per carry of 25 randomly selected running backs 2.8 be used, explain why. Interpret the results are shown below. Assume the yards per carry are normally distributed 2.7 3.7 4.7 7.1 3.7 5.9 2.5...
Use the standard nomal distribution or the distribution to construct a 95% confidence interval for the population mean. Justily your decisioni neither distribution can be used, explain why. Interpret the results In a random sample of 41 people, the mean body mass index (BMI) was 27.8 and the standard deviation was 6.11 Which distribution should be used to construct the confidence interval? Choose the correct answer below. O A Use a distribution because the sample is random, na 30, and...
need help. please this question hace more parts! please i want to put the rest in the comments. so you cna help me out! WSUIT Help Use the standard normal distribution or the distribution to construct a 95% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results In a random sample of 13 mortgage institutions, the mean interest rate was 3.56% and the standard deviation was 0.37%. Assume the...
Use the standard normal distribution or he t-distribution to construct a 90% confidence nterval for the population mean. Justity your decision, f nether distrbuion can be used, explain wihy Inberpnet the resuts In a recent season, the population standard deviation of the yards per carry for all running backs was 1 24 normally distributed yards per carry of 25 randomly selected running backs are shown below Assume the yards per carry are 7.4 4.7 3.7 59 5.6 65 3.8 73...
hi there, having trouble with stats homework In a random sample of 22 people, the mean commute time to work was 31.5 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a t-distribution to construct a 80% confidence interval fo the population mean u. What is the margin of error of u? Interpret the results. The confidence interval for the population mean u is ( 29.4, 33.6) (Round to one decimal place as...