Answer
given that
n = 14
p = 0.40
and r = 12
we have to find the probability of at least 12 of them have brown eyes
using binomcdf
setting n = 14, p = 0.40 and k = 12
P(at least 12) = 1 -binomcdf(n,p,k-1)
= 1 - binomcdf(14,0.40,12-1)
= 1 - binomcdf(14,0.40,11)
= 1 - 0.9994
= 0.0006
= 0.0006*100 = 0.06%
So, this probability is unusual because it is less than 5% probability limit.
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