Question

4. In a given population, 16% of the population has blue eyes and 84% has brown eyes. Although eye color is a polygenic trait, let us assume for this problem that the brown-eyed allele is dominant to the blue-eyed allele and that the population is in Hardy-Weinberg equilibrium. What are the gene frequencies for brown eyed and blue-eyed alleles? = '16 Pa Brown-eyed allele frequency: _ qe 0.4 Pa 0.4 Blue-eyed allele frequency: - In this same population, there are a total of 10,000 people. How many of these people are homozygotes for the brown-eyed allele, heterozygotes, and homozygotes for the blue-eyed allele?

Answer 1

HARDY - WEINBERG EQUILIBRIUM (P+q) = 1 (P+q)² = p²+ q² + 289 = 1 HERE = P - FREQUENCY of DOMINANT ALLELE q= FREQUENCY OF RECESSIVE AUFLE. 02= FREQUENCY Of Homozy GOUS DOMINANT GENOTYPE 2pq- FREQUENCY of HETROZY Gous @ GENOTYPE FREQUENCY OF HOMOZYGOUS RECESSIVE GENOTYPE

IN QUESTION BROWN EYES - DOMINANT BLUE EYES - RECESSIVE so, p2 & 2pq & q² = 1 L BROWN EYES BLUE EYES BOTH HOMOZYGOUS AND METRO ZAGOUS * HETROZYGOUS GENOTYPE WOULD BE WITH BROWN EYES. q² = 16% OR 16 ; a = 0.4

I -0.4 = 0.6 Ptq=1 P = ALLEL FRFOVENCY = BLUE EYED - 0.4 BROWN EYED = 0.6 • PEOPLE WITH HOMOZYGOUS BROWN EYES = pa- (0.6)2 = 0.36 OR 36". 36% OF 10,000 PEOPLE = 3600 PEOPLE ☆ METROZYGOUS BROWN EYES (2 P2)- 2 x 0. 4x Orf = 0.48 of 48% 48% of 10,000 = 4800 PEOPLE PEOPLE WITH BLUE Eyes (22) = (0.4)2 = 0.16 OR 16% : 1600 PEOPLE