Question

In a population of Mendel's garden peas, the frequency of the dominant A (purple flower) allele is 80%. Letp represent the frequency of the A allele and q represent the frequency of the a allele. Assuming that the population is in Hardy-Weinberg equilibrium, what are the genotype frequencies? A. 16% AA, 40 % Aa, 44 % aa B. 80% AA, 10 % Aa, 10 % aa C. 50 % AA , 25 % As , 25 % aa * E. 64% AA, 32% A ... QUESTION 11 which results in tall plants, has a frequency of 0.70, and the allele , which results in dwarf plants, has a frequency of 0.30. In this population, what proportion lele evnected to be mwart?. the plants are , 0.30 B. 0.03 C. 0.25 D.0.09 QUESTION 12 In con, kernel color is determined by two alleles of a single gene; the allele that results in white kernel color (W) is dominant to the allele that results in yellow kernel color (w. In a sample of 100 kernels from a papulation, there are 9 yellow kemels (ww) and 91 white kemels. Assuming that this population is in Hardy-Weinberg equilibrium, what are the frequencies a the two alleles of this gene? B. 0.91 WandO.09 w C. 0.30 W and 0.70 w D. There is nat enough information to detemine this QUESTION 13 Select all correct answers, Which the following statement true about a gene with two alleles in a population that is in Hardy-Weinberg equilibrium? A. The frequencies of the two alleles will remain constant over time. B. The frequencies of the two alleles may change over time C. The frequency of the dominant allele is always greater than the frequency of the recessive allele D.The frequency of the dominant allele is always equal to the frequency of the recessive allele.

Answer 1

10.

Allelic frequency of dominant allele, A = 80% = 0.8

Allelic frequency of recessive allele, a = 1 - 0.8 = 0.2

Genotypic frequency of,

AA = (0.8)² = 0.64 = 64%

2Aa = 2(0.8)(0.2) = 0.32 = 32%

aa = (0.2)² = 0.04 = 4%

Option E

11.

Allelic frequency of allele t = 0.3

Proportion of individuals with dwarf height = genotypic frequency of tt = (0.3)² = 0.09

Option D

12.

Number of kernels with yellow colour, ww = 9

Genotypic frequency of yellow kernel, ww = 9/100 = 0.09

Allelic frequency of yellow kernel, w = √0.09 = 0.3

Allelic frequency of white kernel, W = 1 - 0.3 = 0.7

Option A

13.

Option A

As per Hardy Weinberg equilibrium, frequency of alleles over generations remain constant because no evolutionary force (mutation, migration, selection, random mating, large population) is acting on the population. The population is said to be ideal.

14.

Number of red beetles in population A, RR + Rr = 75%

Number of brown beetles in population A, rr = 25%

Genotypic frequency of brown beetles, rr = 0.25

Allelic frequency of r allele = √0.25 = 0.5

Allelic frequency of R allele = 1 - 0.5 = 0.5

Number of brown beetles in population B, rr = 49%

Genotypic frequency of r allele in population B = 49% = 0.49

Allelic frequency of r allele = √0.49 = 0.7

Allellic frequency of R allele = 1 - 0.7 = 0.3

	R	r
Population A	0.5	0.5
Population B	0.3	0.7

Population A has greater R allele frequency.

Option C

15.

Same as question 14.

Heterozygotes for population A = 2(0.5)(0.5) = 0.5 = 50%

Heterozygotes for population B = 2(0.3)(0.7) = 0.42 =42%

Option C

16. Option D

We found that the number of red bettles in population A and C were same. So, their genotypic frequencies will also be same. The proportion of brown bettles will also be same. Allelic frequency of R and r will be same in both the populations. Therefore, no evolutionary force may be acting on the population and population will be in HWE.

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