Question

1. A population of 2000 peppered moths has the following genotypic frequencies:aa: 0.16, Aa: 0.04. AA: 0.80. a. The frequency of the 'a' allele in this population is (show your work for full credit): frequency of the a allele is __ . Calculate the expected genotypic frequencies under Hardy-Weinberg equilibrium. Is this population in equilibrium for genotypic frequencies? Show all your work for full credit. (Do a rough comparison by eye of the observed and expected frequencies to test for equilibrium; for lecture you do not need to do Chi Square tests, but you do need to know how to do Chi Square tests for lab.) yes or no? 2. A species of snail comes in two colors: brown and black. Color is determined by alleles at a single locus, where the black allele is dominant to the brown allele. Last week, twenty snails belonging to this species were introduced into a park already containing snails in Sacramento: 64% of the introduced snails were brown, and 36% were black. Based on these data, you can conclude that the frequency of the black allele in the entire park population is: a) 0.40 b) 0.60 c) 0.24 d) 0.80 e) not something you can calculate for the above situation 3. If the frequency of the Callele is 0.2 in a population with only 2 alleles at this locus, what will the frequency of heterozygotes be, if the population is in Hardy-Weinberg equilibrium? a) 0.04 b) 0.16 c) 0.32 d) 0.64 e) 0.80

Answer 1

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Answer 1- a) Aa The frequency of a allelc is: genotypic frequency of aa + 1 genotypic Frequency - 0.16 + 1x0.04 - 0.16+0.02 -0.18 5) The frequency of A allee is 1- Q-1-0.18 = 0.82 Observed AA 0.80 Aa 0.04 aa 0.16 | Expected! 1(A)2 (08212= 0.6724 2xAxa - 2x0.82X0.18 = 0.2952 [(a)2= (0.18)² = 0.0324 As you see that observed and expected genotypic frequency have significant difference. Hence population is not in H.W.E. No Answer 2 - of genotypic frequency of black (99) = 0.36 Alldic frequency of black allele lu) = 129 -10:36 = 0.6 B is right ansnier Answier 3: The frequency of ic allel allile is l-C Heterozygous - 2xCxc= 2x0.2x0.8:0.32 - ¢ is the right answer - -0-2-0-8

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